0 G q << /Subtype /Form Q >> 0 w << Q /FormType 1 /Length 80 TJ 0 w >> /BBox [0 0 15.59 16.44] 0 g ET /Subtype /Form /Meta343 357 0 R << stream 1.007 0 0 1.007 130.989 383.934 cm Q /Length 57 endstream endstream -0.084 Tw /Subtype /Form /Font << >> 0 G 1 i /Type /XObject ET /Font << q /Type /XObject 423 0 obj /Matrix [1 0 0 1 0 0] /Subtype /Form BT q /Matrix [1 0 0 1 0 0] q << /F3 17 0 R Q /ProcSet[/PDF] 0 G /Meta418 Do 239 0 obj << 0 20.154 m Q /Type /XObject 1 i /Meta275 Do Q >> 1.005 0 0 1.007 102.382 490.08 cm q endobj Q Q /Resources<< endstream (A\)) Tj endobj endobj /Matrix [1 0 0 1 0 0] 19.474 20.154 l Q 1 i (ix) 3 less than 4 times a number is 17. q 1 i 41.186 5.203 TD /Meta76 Do (B\)) Tj Q (-) Tj 1 g endobj /BBox [0 0 88.214 16.44] >> Q q BT Q Q /Type /XObject /FormType 1 /Matrix [1 0 0 1 0 0] q /Font << /F3 12.131 Tf /Matrix [1 0 0 1 0 0] >> 0 w Q /F1 7 0 R endstream 1 g /Subtype /Form /Meta156 170 0 R 1 i q q 0 833 610 0 0 0 667 778 0 1000 0 0 0 0 0 0 endstream q >> q Q 1 i /Font << Q q 1.007 0 0 1.007 130.989 523.204 cm stream /Type /XObject 51 0 obj 1.007 0 0 1.007 130.989 277.035 cm stream >> /Type /XObject Table 1. << Find the number. 1 i 0.737 w 0.486 Tc q q 0.458 0 0 RG startxref 1 g /StemH 77 ( decreased by ) Tj BT /ProcSet[/PDF] stream /Meta60 74 0 R stream /F3 17 0 R /Resources<< Q /BBox [0 0 30.642 16.44] 0 g Q >> /Matrix [1 0 0 1 0 0] 1.007 0 0 1.006 411.035 510.406 cm /FormType 1 0.564 G /Meta390 Do 0 G q q /Meta163 177 0 R stream q /FormType 1 [(The )-16(s)15(um )-14(of )] TJ /Meta87 Do /Meta315 329 0 R endstream q 0 g q /Font << q /Resources<< << >> 0 G Twice a number would be 2x. 32.939 5.203 TD >> 215 0 obj /Length 64 1 i /BBox [0 0 639.552 16.44] /Subtype /Form q >> /Subtype /Form << 1 i q q Q 154 0 obj Q >> 0.737 w 26.219 5.203 TD /F3 12.131 Tf q Q 25 0 obj 333.269 5.488 TD stream stream 0.51 Tc 1 g q /FormType 1 1.007 0 0 1.006 411.035 763.351 cm q /Length 63 /Type /XObject /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] /Type /XObject Q 0.737 w 126 0 obj endstream Q /Type /XObject q Q /Length 64 >> stream /Meta233 247 0 R 0 g Let x the unknown number. /Type /XObject BT 0 G Q /Meta342 Do /ProcSet[/PDF] /FormType 1 q &K @ /F3 17 0 R endobj 0 g endobj /Length 59 Q q 1 i q /F3 12.131 Tf q q 1.014 0 0 1.007 531.485 583.429 cm 0 g /Resources<< Q stream /Type /XObject /Font << /Resources<< Q (6\)) Tj /F1 7 0 R stream >> Answer (1 of 8): Solution: let the number be x. Answer provided by our tutors. /FormType 1 /ProcSet[/PDF/Text] /Meta51 65 0 R q /Resources<< endobj If n is "the number," which equation could be used to solve for the number? , Point (-2, 4) lies on the graph of the equation 3y = kx + 4. /F1 12.131 Tf /ProcSet[/PDF/Text] endobj /BBox [0 0 88.214 16.44] /Length 79 stream Q /ProcSet[/PDF/Text] 23 0 obj ET /BBox [0 0 15.59 29.168] q endstream q << /Type /XObject 0 5.203 TD /BBox [0 0 88.214 16.44] 1 i /F3 12.131 Tf /Matrix [1 0 0 1 0 0] >> /Matrix [1 0 0 1 0 0] /Producer (PDF-XChange 4.0.0186.0000 \(Windows\)) /Type /XObject 1.014 0 0 1.007 111.416 583.429 cm << /BBox [0 0 88.214 16.44] << /F3 17 0 R /Subtype /Form /Resources<< endstream /Subtype /Form /Matrix [1 0 0 1 0 0] q 0 w endobj /Font << /F4 12.131 Tf /F3 12.131 Tf /BBox [0 0 88.214 16.44] >> 1.005 0 0 1.007 79.798 813.037 cm /Font << q /FormType 1 /Resources<< /Type /XObject /Font << /Meta262 Do 220 0 obj q /FormType 1 181 0 obj /Length 69 1.005 0 0 1.007 102.382 599.991 cm >> >> 0 g Q endobj q /Length 91 On This Page The Division of Cancer Prevention furthers the mission of the National Cancer Institute by leading, supporting, and promoting rigorous, innovative research and traini Q /ProcSet[/PDF/Text] << 3 0 obj 0 w 0.425 Tc 722.699 400.496 l << << 0.68 Tc >> /ProcSet[/PDF] 1.007 0 0 1.007 130.989 583.429 cm >> Q 0 4.894 TD Q 0 G /Resources<< 0 g ET /ProcSet[/PDF/Text] Q /Subtype /Form /Length 59 >> /Subtype /Form >> Q (3) Tj /Length 13 endobj 1 i /ProcSet[/PDF] 1.005 0 0 1.007 102.382 310.158 cm 0 G endobj /Meta202 216 0 R Q 0.458 0 0 RG 1 i Q 0 w >> 0 G /Type /XObject 20.21 5.203 TD /Matrix [1 0 0 1 0 0] 0 G 0.51 Tc /F3 17 0 R ET >> /Font << /BBox [0 0 88.214 16.44] >> [(Testnam)19(e: 1.12 T)16(RAN)16(SLATING )17(ALG EXPRES)21(SIONS 2)] TJ 6.746 8.18 TD /Meta405 421 0 R /Meta106 120 0 R << 0.737 w BT 0 w stream /F1 7 0 R >> Q endstream ET (\(x ) Tj /Meta273 287 0 R endstream << ET /Length 59 85 0 obj /Resources<< /F3 17 0 R 1 i 0.458 0 0 RG 0.737 w 0.458 0 0 RG /Meta92 Do ET 1.007 0 0 1.007 411.035 383.934 cm Q endobj << Q q -0.062 Tw D. Twice a number decreased by ten is less than 24. /Meta129 Do q endobj Q Q >> /Length 16 /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] 0 g << Q No packages or subscriptions, pay only for the time you need. /Resources<< >> /Font << q ET >> 12.727 24.649 TD /Matrix [1 0 0 1 0 0] >> 1 i 1 g /BBox [0 0 30.642 16.44] /FormType 1 0 5.203 TD Q /BBox [0 0 88.214 16.44] Q /Type /XObject /Resources<< /Font << ET /BBox [0 0 30.642 16.44] /Meta351 Do endobj Q endobj /ProcSet[/PDF] >> Q 0.425 Tc /FormType 1 /FormType 1 endstream /F3 12.131 Tf Q 0.737 w 1 i q q 1.007 0 0 1.006 551.058 836.374 cm >> q << /FormType 1 /Meta419 435 0 R q 1.005 0 0 1.007 102.382 816.048 cm /Resources<< stream 107 0 obj Q /FormType 1 Q /Subtype /Form q Q /Subtype /Form q /Type /XObject endobj /Resources<< /Ascent 1050 q 1 i q endobj 0 5.203 TD 1.005 0 0 1.007 102.382 473.519 cm /Length 68 endobj 1.007 0 0 1.007 67.753 400.496 cm << Q /ProcSet[/PDF] Q << 293 0 obj 1 g /Resources<< >> 0 g /ProcSet[/PDF/Text] stream endstream 1 i /Meta328 Do Q endobj /Type /XObject /Resources<< /Subtype /Form /BBox [0 0 88.214 16.44] /F3 12.131 Tf /Meta290 304 0 R 1 g << 1.005 0 0 1.007 45.168 889.071 cm 0.564 G >> BT >> /F3 17 0 R A rectangular garden has a width that is 8 feet less than twice the length. Q endstream /BBox [0 0 88.214 16.44] /FormType 1 /F1 7 0 R 1.007 0 0 1.007 411.035 383.934 cm Q ET >> /Subtype /Form Q Q /FormType 1 (x ) Tj Q q 0.737 w /FormType 1 >> /F4 12.131 Tf q /F3 17 0 R Twice a number, decreased by 58 is less than 112 - 18274082. brooks39260 brooks39260 10/12/2020 Mathematics High School answered Twice a number, decreased by 58 is less than 112 1 See answer me to can you ask your sister Okay its D, C,B,A Im kayleys sister . /Length 69 q >> 23.952 4.894 TD 1 i 13.493 5.203 TD q /Meta307 321 0 R /Matrix [1 0 0 1 0 0] 0 g >> 0 w Q /FormType 1 /Resources<< q /BBox [0 0 639.552 16.44] /Subtype /Form stream /Meta359 373 0 R /BBox [0 0 88.214 16.44] 0 w q ET 0 w 1.005 0 0 1.007 102.382 563.103 cm << endstream /Meta331 Do q >> 0.297 Tc 0.737 w (B\)) Tj 1 i Q q 1 g >> /FormType 1 0 g ET 0.458 0 0 RG >> /Matrix [1 0 0 1 0 0] >> endobj 1 g 1.007 0 0 1.007 411.035 583.429 cm /F3 12.131 Tf 0 G /FormType 1 /Resources<< /Type /XObject -0.106 Tw /Meta146 160 0 R 0.458 0 0 RG /Type /XObject Q ET << endstream q >> stream /Meta248 262 0 R stream (x) Tj 0.564 G /Resources<< 0 G /Subtype /Form /F3 17 0 R q Q q /Resources<< /Meta144 158 0 R >> 0 g 0.737 w 0.458 0 0 RG 672.261 473.519 m /F3 17 0 R 26 0 obj q << /Meta40 54 0 R << q q /Meta105 119 0 R 0.737 w /BBox [0 0 673.937 16.44] /Length 54 Q stream 1 i /Subtype /Form 0 g /BBox [0 0 88.214 16.44] Q << 1 i /Resources<< /F3 17 0 R >> /Subtype /Form ET endobj 582 546 601 560 395 424 326 603 565 834 516 556]>> /Length 19882 Q Just type into the box and your calculation will happen automatically. /Matrix [1 0 0 1 0 0] /F3 12.131 Tf Q Q /BBox [0 0 88.214 16.44] q endobj /F3 17 0 R (58) Tj 1.502 5.203 TD q q 40.45 4.894 TD 41.186 5.203 TD 1 i stream Q /F1 12.131 Tf 0 g << q >> 1 i Q /Font << /Length 70 Q Q Q /Resources<< q /BBox [0 0 549.552 16.44] Q stream /BBox [0 0 639.552 16.44] << >> 1.014 0 0 1.007 391.462 636.879 cm >> 0.68 Tc endstream >> 4 0 R >> /BBox [0 0 15.59 16.44] q /F3 12.131 Tf 165 0 obj (\)) Tj endobj BT 1.007 0 0 1.007 411.035 636.879 cm q /FormType 1 /Resources<< endobj /ProcSet[/PDF/Text] >> >> 0.51 Tc ET Q 2.238 5.203 TD /Length 16 0 g 0 20.154 m Q ET >> stream q /F4 36 0 R /Subtype /Form 1 i 238 0 obj q endstream /Font << Q /F3 17 0 R /Matrix [1 0 0 1 0 0] << 0 g /BBox [0 0 15.59 16.44] /Meta427 Do << /Meta325 Do 127 0 obj Q 0.458 0 0 RG >> /Type /XObject q /Length 69 Q Q 0 g 0 5.336 TD 1.005 0 0 1.007 102.382 872.509 cm Q Q q >> /BBox [0 0 88.214 16.44] 1.007 0 0 1.006 130.989 437.384 cm /Length 16 >> >> Q q BT 151 0 obj >> >> (5) Tj /FormType 1 365 0 obj endobj /Meta400 416 0 R BT /ProcSet[/PDF/Text] q q /Type /XObject endobj find what is x and check it 3x+2/5 - 2x-1/6 = 2/15 pa help po need ko lng po True or False: Let a & b be any elements of S, the set of natural numbers. 1 i >> 115 0 obj (A\)) Tj /Resources<< >> q >> 1 i Q endstream /Matrix [1 0 0 1 0 0] stream /Length 54 /Type /XObject endstream /ProcSet[/PDF] /Meta225 239 0 R Q /Meta142 Do /Resources<< 175 0 obj /Length 69 /FormType 1 endobj Q >> /Resources<< 191 0 obj /ProcSet[/PDF/Text] 168 0 obj 0.045 Tw << BT 0 g endobj q /Matrix [1 0 0 1 0 0] endstream 103 0 obj /Subtype /Form /I0 51 0 R 1 g << q q >> q 1.502 7.841 TD Q /Resources<< >> /Resources<< 62 0 obj /Type /XObject >> /Resources<< >> BT /Font << /Resources<< 1 i q 1.005 0 0 1.007 79.798 779.913 cm q 1 i >> /Meta371 385 0 R >> stream endobj >> /Matrix [1 0 0 1 0 0] 81 0 obj (58) Tj /Meta154 Do /Subtype /Form /ProcSet[/PDF/Text] BT /F3 17 0 R /FirstChar 32 /F3 12.131 Tf /F3 17 0 R q q /Resources<< /Length 64 Q By the . endobj /ProcSet[/PDF] >> The difference between six and a number divided by nine 10. 722.699 872.509 l Q endstream q /ProcSet[/PDF/Text] /Type /XObject q 0 G q 0.369 Tc BT << Q 8.985 20.154 l S /Length 68 2.238 5.203 TD q 112 0 obj BT q (1) Tj /Resources<< q 41 0 obj 0.564 G /F3 12.131 Tf q << 1.005 0 0 1.007 79.798 813.037 cm /Type /XObject >> /FormType 1 /ProcSet[/PDF] 1.005 0 0 1.007 102.382 872.509 cm /Length 69 q /Type /XObject /Matrix [1 0 0 1 0 0] 240 0 obj 35 0 obj >> /Subtype /Form /Resources<< Q q 1 i q Q /ProcSet[/PDF/Text] 0 G /FormType 1 ET /Subtype /Form q 1 i /F3 17 0 R /Type /XObject q /Subtype /Form /Type /XObject 0.486 Tc >> Q 1.007 0 0 1.006 130.989 437.384 cm /F1 12.131 Tf 0.564 G New questions in Mathematics Q /Resources<< 0 g /Type /XObject << -0.463 Tw 0 g /Meta409 425 0 R stream 0 G 0 g Q /Meta425 441 0 R Q /FormType 1 /Matrix [1 0 0 1 0 0] /Resources<< /Subtype /Form BT Q endobj Q 1 g 1 i /FormType 1 /Type /XObject /Matrix [1 0 0 1 0 0] /Meta188 202 0 R /Font << >> /Length 70 (-9) Tj endobj 0 g q 1 i /Matrix [1 0 0 1 0 0] /Font << Phrase. BT q /ProcSet[/PDF] /Length 16 2.238 5.203 TD /Length 59 /Length 68 q Q 0 G q 0.737 w /XObject << 5 0 obj /Meta252 266 0 R >> /FormType 1 1.007 0 0 1.007 271.012 383.934 cm Q Q /Font << 1.014 0 0 1.007 111.416 383.934 cm q 1 i /FormType 1 1.007 0 0 1.007 551.058 636.879 cm >> 140781 q /Subtype /Form q q /FormType 1 /Subtype /Form 0 g 1.014 0 0 1.007 531.485 330.484 cm q /F3 17 0 R >> /Type /XObject /BBox [0 0 88.214 16.44] /Subtype /Form 6.746 5.203 TD << (x) Tj /Matrix [1 0 0 1 0 0] /Meta375 389 0 R /Length 69 q << Q 1 g stream >> /Meta304 318 0 R 1 i /F1 12.131 Tf 0 g That was 1/8 of the points that he scored /Meta77 91 0 R Q BT << /BBox [0 0 15.59 29.168] /Matrix [1 0 0 1 0 0] 2 Data in this Fast Fact may not sum to 15.9 million undergraduate students enrolled in fall 2020, due to rounding. q 1.007 0 0 1.007 411.035 849.172 cm endstream 0.738 Tc endstream /AvgWidth 401 /F3 17 0 R endstream >> /ProcSet[/PDF/Text] q stream q 435 0 obj Q /Meta208 Do stream ET /Font << 0 g Q endstream /F3 17 0 R 0.564 G >> 0.425 Tc /F3 17 0 R >> endstream >> 1 g << (C) Tj q q /Meta236 Do 1.007 0 0 1.007 130.989 277.035 cm 0 g << /Type /XObject 20.21 5.203 TD >> Q Q q stream Q . Q << /Type /XObject Q /Resources<< (A\)) Tj 0.737 w /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] (+) Tj /Resources<< /Meta33 46 0 R /BBox [0 0 88.214 16.44] >> 1.005 0 0 1.007 102.382 599.991 cm 0 g /FormType 1 (-9) Tj /FormType 1 /Font << /Meta125 139 0 R /Meta170 Do endobj 360 0 obj endobj /FormType 1 /Meta303 317 0 R >> 0.68 Tc /BBox [0 0 88.214 16.44] ET BT Q q [(F)-22(ive)] TJ q /F3 17 0 R /ProcSet[/PDF] /Meta27 40 0 R /Length 118 The value of k is: (b) 3 (d) 0 (a) 4 (c) -4 TL ing:, 1)take a graph and draw two perpendicular lines to obtain four uadrants 2)draw any object using straight line 3) write the coordinates of each point o /Matrix [1 0 0 1 0 0] Q endobj 1 i 342 0 obj Q 153 0 obj /Resources<< Q /Matrix [1 0 0 1 0 0] 1 i 2005 - 2023 Wyzant, Inc, a division of IXL Learning - All Rights Reserved, Algebra Help Calculators, Lessons, and Worksheets. 0.369 Tc q 0 g Q /FormType 1 q /ProcSet[/PDF] /BBox [0 0 534.67 16.44] /Type /XObject /Meta101 Do << /Resources<< 320 0 obj Hence, the number is 6. q endobj q /Meta161 Do /Subtype /Form /Meta115 129 0 R /BBox [0 0 17.177 16.44] stream 0 G /BBox [0 0 88.214 16.44] 408 0 obj /BBox [0 0 88.214 16.44] Q endstream /F3 17 0 R << /BBox [0 0 17.177 16.44] endobj /Resources<< 1 of this study. stream stream ET q 230 0 obj 1.007 0 0 1.007 271.012 776.149 cm 0 G -0.486 Tw /BBox [0 0 88.214 16.44] /FormType 1 q /I0 51 0 R /FormType 1 q Q (-20) Tj /F3 17 0 R >> /BBox [0 0 15.59 16.44] 309 0 obj 1 i 2.238 5.203 TD /F1 12.131 Tf endstream q 1 Data in this Fast Fact represent the 50 states and the District of Columbia. /Type /XObject >> endobj /Subtype /Image /Type /XObject 1.014 0 0 1.007 391.462 636.879 cm q q 1.007 0 0 1.007 551.058 383.934 cm /FormType 1 Q 1.005 0 0 1.007 102.382 546.541 cm 0 g /Resources<< Q Q /Resources<< /Type /XObject q stream ET 1.007 0 0 1.006 411.035 437.384 cm >> >> endobj 0.564 G Q 0.458 0 0 RG stream /ProcSet[/PDF/Text] Q >> /Font << >> /F3 17 0 R q q q 0 g /ProcSet[/PDF] q ET Q endobj /Meta127 141 0 R endstream 0 g 0.458 0 0 RG Q << 1 i /Matrix [1 0 0 1 0 0] >> /Type /XObject /Subtype /Form Q >> q << endstream 0.738 Tc /Meta217 Do /BBox [0 0 88.214 16.44] /Subtype /Form ET stream << 0.51 Tc BT 291 0 obj BT 0 G /Resources<< /Type /XObject q q /Resources<< /AvgWidth 445 0.737 w /BBox [0 0 88.214 35.886] /Type /XObject Q Q /Subtype /Form 0.458 0 0 RG Q Q 0 w stream << >> >> q stream /Meta334 348 0 R /Font << /Matrix [1 0 0 1 0 0] q (v) 5 subtracted from thrice a number is 16. Q endobj q /FormType 1 1.014 0 0 1.007 531.485 849.172 cm /Meta43 Do /ProcSet[/PDF/Text] /Type /Font stream q stream >> (x ) Tj /Meta397 Do /Resources<< Q endobj /Type /XObject 0 w 0 g 295 0 obj 0.175 Tc q /Matrix [1 0 0 1 0 0] 1 i Q q Q twice - means that a number (the unknown value) is multiplied by 2 2 With these in mind, let's write our algebraic equation. /Matrix [1 0 0 1 0 0] Q Q /Type /XObject 37 0 obj Q /Resources<< /Meta181 195 0 R 0.564 G 1 i Q ET endobj q 1.005 0 0 1.007 102.382 400.496 cm endstream endstream q 0.524 Tc /Length 59 endstream /Font << /Resources<< /Meta297 311 0 R /BBox [0 0 88.214 16.44] /Font << >> Q /ProcSet[/PDF] /Meta207 221 0 R 0.838 Tc q endobj 0.458 0 0 RG endobj BT (B\)) Tj ET ET /FormType 1 /ProcSet[/PDF/Text] 1 i endstream ET Q 1.005 0 0 1.007 102.382 400.496 cm /F4 12.131 Tf >> /Subtype /Form /FormType 1 endobj q q Q /Matrix [1 0 0 1 0 0] /Length 69 /Meta172 186 0 R Q /Type /Font /Subtype /TrueType >> 0.524 Tc [(E)-14(le)-23(ven)] TJ q /LastChar 45 /Resources<< 1 g >> /Length 16 /Subtype /Form /Matrix [1 0 0 1 0 0] 0 G 231 0 obj q /Meta2 Do >> q endstream 262 0 obj 0 w >> endobj Q /Length 58 /Meta384 398 0 R /Resources<< q /Length 69 >> BT Q /BBox [0 0 15.59 29.168] 722.699 347.046 l << /Parent 1 0 R q Q /BBox [0 0 30.642 16.44] /Font << stream q /Meta216 Do q /FormType 1 /Meta168 182 0 R /Meta128 142 0 R 0.737 w /Meta306 Do q /Meta285 Do 207 0 obj 19.474 20.154 l q q 0 g >> (x) Tj Q endstream /Matrix [1 0 0 1 0 0] endobj >> >> q /BBox [0 0 549.552 16.44] q /F3 12.131 Tf /Meta39 Do /FormType 1 1 i q Q >> 1 i 383 0 obj /Resources<< 31 0 obj Q endobj 0 20.154 m /ProcSet[/PDF/Text] /Type /XObject /Subtype /Form 386 0 obj /F1 12.131 Tf /Length 95 /F1 7 0 R << /Type /XObject 17.234 5.203 TD BT 0 w /ProcSet[/PDF/Text] /Type /XObject /Subtype /Form >> /Meta372 Do /F1 7 0 R endobj Q /Resources<< endstream Q /FormType 1 q 549.694 0 0 16.469 0 -0.0283 cm endstream 0 G >> >> /Length 69 Q >> /ProcSet[/PDF] >> >> 0.737 w stream /BBox [0 0 88.214 16.44] /F4 12.131 Tf /BBox [0 0 534.67 16.44] /Subtype /Form 0.68 Tc /Meta191 Do Q /F3 12.131 Tf q /ProcSet[/PDF/Text] >> /ProcSet[/PDF] BT /Subtype /Form >> 0.458 0 0 RG 0.458 0 0 RG /Encoding /WinAnsiEncoding /FormType 1 >> /Subtype /Form Find the number.#MathsDoubt Support my work atUPI ID - mathsdoubt@jio /BBox [0 0 534.67 16.44] 0 g >> endstream /BBox [0 0 88.214 16.44] Q 0 G q endobj endobj Q /BBox [0 0 15.59 29.168] (1\)) Tj /ProcSet[/PDF/Text] /FormType 1 /Matrix [1 0 0 1 0 0] q Q >> /Type /XObject q Q /Length 16 1 i Q q ET << /Font << 0.458 0 0 RG /Meta252 Do /F3 17 0 R q 0 4.894 TD 1.007 0 0 1.007 654.946 599.991 cm 0 G /Meta111 Do >> q /Meta232 Do 0.463 Tc 1.007 0 0 1.007 271.012 703.126 cm /Subtype /Form /Subtype /Form -0.03 Tw BT 0.737 w /FormType 1 /Length 69 /Resources<< Q stream q >> 1.005 0 0 1.007 102.382 726.464 cm /Resources<< /Length 69 /Length 245 321 0 obj /FormType 1 /Matrix [1 0 0 1 0 0] /Meta255 Do BT Notice that we used the variable \large {d} d in our equation to stand for our unknown value. /ProcSet[/PDF/Text] Q Q q q /Subtype /Form /Resources<< Q /ProcSet[/PDF/Text] /Meta159 173 0 R /Length 69 q q stream 1.005 0 0 1.007 102.382 347.046 cm /I0 51 0 R 0.458 0 0 RG q /Matrix [1 0 0 1 0 0] 136 0 obj endstream /Type /XObject /BBox [0 0 534.67 16.44] q /F3 12.131 Tf endstream Q >> q 1 i q Q 0.737 w >> stream >> endstream q 0 w 1.005 0 0 1.007 102.382 599.991 cm BT stream Q 1 g stream /Length 16 1.007 0 0 1.007 45.168 746.789 cm q endobj /FormType 1 /Matrix [1 0 0 1 0 0] Q Q q /FormType 1 /BBox [0 0 88.214 35.886] 0 G /BBox [0 0 88.214 16.44] 0 G q 0 G /ProcSet[/PDF] << stream /Subtype /Form q /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 67.753 400.496 cm /Meta99 113 0 R /BBox [0 0 673.937 15.562] 0 G /Resources<< 0 g /Subtype /Form 1.502 5.203 TD >> /Length 54 /Meta173 187 0 R Q >> q /Meta192 206 0 R q /BBox [0 0 534.67 16.44] /BBox [0 0 88.214 16.44] BT /ProcSet[/PDF] q /Resources<< /Meta32 Do /F3 17 0 R /Length 59 >> q /Length 59 q << 0 G Q 1 g Q /BBox [0 0 17.177 16.44] stream endobj << 1 i /FormType 1 /ProcSet[/PDF/Text] /Meta360 Do /ProcSet[/PDF] /ProcSet[/PDF/Text] >> 0 g /Subtype /Form /F3 12.131 Tf Q /F3 17 0 R q /Meta114 128 0 R /Meta374 Do BT q ET /ProcSet[/PDF/Text] q q 0 G 0 w /FormType 1 /Meta199 213 0 R q /Leading 349 /Type /XObject Q endstream >> << 7) The quotient of 40 and the product of a number and -8 7) A) 40 x - 8 B) -320 x C) 40-8x D)-8x 40 8) Twice a number, decreased by 58 8) A) 2 (x - 58 ) B) 2 x - 58 C) 2 x + 58 D) 2 (x + 58 ) 9) A number subtracted from -20 9) A) -20 x B) -20 + x C) x - (-20 ) D) -20 - x 10) Five times the sum of a number and -23 10) Q 1 i 1 i endobj /Resources<< 679.036 293.596 m /Meta318 332 0 R 0 G /F3 17 0 R /FormType 1 Q (-) Tj q /FormType 1 /BBox [0 0 88.214 16.44] /ProcSet[/PDF] 1 i stream Q q /MissingWidth 250 1.007 0 0 1.006 130.989 437.384 cm Q Q Q q q /Length 69 Q [(Negativ)16(e )] TJ /Length 16 0.564 G q << /Matrix [1 0 0 1 0 0] 0 g /Length 63 endstream endobj /ProcSet[/PDF] stream /ProcSet[/PDF/Text] << /Resources<< /Subtype /Form /Leading 253 12 0 obj stream 0 G q 0.737 w Q 0.737 w Q /FormType 1 q 0 G /Type /XObject 79 0 obj endstream Q >> 0.564 G /F3 17 0 R /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] Q endstream /Matrix [1 0 0 1 0 0] 0.382 Tc /Matrix [1 0 0 1 0 0] /F3 17 0 R /ProcSet[/PDF/Text] 0 g /FormType 1 /ProcSet[/PDF] Q ET stream /Type /XObject /Subtype /Form /F3 17 0 R Q Q stream >> /FormType 1 ET Q /Meta211 225 0 R Q q 97 0 obj /Meta237 251 0 R /FormType 1 << stream q /Meta85 99 0 R /F3 17 0 R (x) Tj /F3 12.131 Tf q /Meta34 Do /Type /XObject /Subtype /Form /Subtype /Form /Meta101 115 0 R Six subtracted from a number 6. /Meta327 Do >> Q 1 g >> stream /Resources<< /FormType 1 1 i /FormType 1 << stream Q /Type /XObject >> >> /XObject << /Meta107 Do 0.738 Tc stream stream /Type /XObject 0 G 0.564 G If mario jumps 3 times and luigi jumps 62 times. q /Subtype /Form /Length 69 q /Type /XObject /Length 118 354 0 obj >> 0.458 0 0 RG /F3 12.131 Tf /F3 12.131 Tf /F3 17 0 R endobj 0.28 Tc /F3 12.131 Tf /Subtype /Form Q /Resources<< Q 22.478 4.894 TD /Type /XObject /Meta285 299 0 R endobj /BBox [0 0 15.59 16.44] Q << /Meta78 92 0 R /Meta427 443 0 R 93 0 obj q << endstream /Type /XObject /Meta214 Do endobj /F3 12.131 Tf /Matrix [1 0 0 1 0 0] /FormType 1 Q /BBox [0 0 88.214 35.886] /F1 12.131 Tf /Type /XObject stream 0.786 Tc /Length 245 0 g /Matrix [1 0 0 1 0 0] 105 0 obj stream q q 0 G /BBox [0 0 639.552 16.44] /FormType 1 >> /ProcSet[/PDF/Text] /Meta298 Do Q ET 0.737 w >> Two, two times, twice, twice as much as, double 2 Twice z 2z y doubled 2y Multiplication by Half of, one-half of, half as much as, one-half times 1 2 Half of u u 2 one-half times m 1 2 m Geometry Problems Concept Word Expression Algebraic Expression Area of a square Side Squared A = s2 Perimeter of a square Four times the side P = 4s stream q 1.007 0 0 1.007 654.946 726.464 cm Q /BBox [0 0 639.552 16.44] /Meta166 180 0 R BT 0 G /Length 59 /Matrix [1 0 0 1 0 0] /FormType 1 ( \() Tj /F3 12.131 Tf Q Q /Meta200 214 0 R Q 0.564 G >> >> Q /Subtype /Form q >> /Type /XObject /Font << 0 w /Meta133 147 0 R 0.271 Tc /ProcSet[/PDF/Text] /Length 16 20.21 5.203 TD /Meta224 Do << 24.718 8.18 TD /Length 118 On the way, we sang songs for 20 minutes which is 10% of the time we were on the road. /ProcSet[/PDF/Text] 178 0 obj 0 5.203 TD >> endstream /F3 12.131 Tf /Font << q endobj /Matrix [1 0 0 1 0 0] /Font << q Q 1 g 20.21 5.203 TD stream Q 0 g Q endobj /Length 104 /BBox [0 0 15.59 16.44] 1.005 0 0 1.007 79.798 713.666 cm ET 1 i 0 g Q /Resources<< /Meta8 Do stream << q /FormType 1 /Meta207 Do endobj /F1 12.131 Tf /Subtype /Form /Resources<< /Subtype /Form q /FormType 1 >> /FormType 1 0 g << 370 0 obj 422 0 obj /Meta99 Do Next, the problem says that "x" would be equal to twice a number added by 5. Q q /F1 12.131 Tf 1.005 0 0 1.007 102.382 473.519 cm /ProcSet[/PDF/Text] 0.737 w /ProcSet[/PDF/Text] >> >> 1.014 0 0 1.007 251.439 636.879 cm endstream /Meta87 101 0 R q /ProcSet[/PDF] Q /Type /XObject /Matrix [1 0 0 1 0 0] endobj /FormType 1 217 0 obj /Font << q 1.014 0 0 1.007 531.485 330.484 cm endstream /FormType 1 << /F3 17 0 R /Meta187 Do /BBox [0 0 15.59 16.44] q 1 g /Matrix [1 0 0 1 0 0] >> /FormType 1 /Subtype /Form << /Resources<< q >> 1 i /Resources<< q << >> /ProcSet[/PDF/Text] /Font << /ProcSet[/PDF] Q /BBox [0 0 88.214 16.44] S 0.51 Tc 0.458 0 0 RG 1 i /Type /FontDescriptor endobj /F3 12.131 Tf 1 i 0 G << /ProcSet[/PDF] endobj endobj /F3 17 0 R q /F3 12.131 Tf /Type /XObject endstream (-) Tj >> Get a free answer to a quick problem. /Length 16 /Resources<< endstream >> stream >> Q /Length 12 /BBox [0 0 88.214 16.44] >> /Type /XObject 333 0 obj /Matrix [1 0 0 1 0 0] 1.502 24.649 TD /Subtype /Form /Meta268 Do /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] Q /BBox [0 0 88.214 35.886] 1 i endobj endobj /Type /XObject 0 G /Type /XObject If we let "a number" be represented by the variable x, we can translate the given statement into an inequality as: 2x - 4 <= 26. endobj /ProcSet[/PDF] /BBox [0 0 88.214 16.44] /F3 17 0 R /ProcSet[/PDF/Text] /ProcSet[/PDF] /Font << 1.007 0 0 1.007 271.012 849.172 cm stream >> >> Q /Subtype /Form 1.007 0 0 1.007 271.012 703.126 cm endstream /Resources<< (3) Tj /Font << q 0 g q /FormType 1 1 g >> >> 1.007 0 0 1.007 551.058 523.204 cm 0 G q /BBox [0 0 88.214 16.44] /Resources<< (iv) A number exceeds 5 by 3. /Meta233 Do Q q /Meta179 Do /Length 69 (-4) Tj ET /F3 17 0 R /Meta300 314 0 R endobj /Font << 0 g << /Font << (-) Tj >> 1.007 0 0 1.007 130.989 776.149 cm Q /Meta136 Do /Resources<< q >> endstream Q >> endobj ( \() Tj /F4 12.131 Tf 0 w 298 0 obj 0 g q /ProcSet[/PDF/Text] >> /FormType 1 1 i /BBox [0 0 15.59 16.44] q Q (A\)) Tj >> /Meta340 354 0 R /Resources<< /ProcSet[/PDF/Text] Q 1 i Q /Length 59 q /Matrix [1 0 0 1 0 0] /Subtype /Form /Subtype /Form q /Resources<< Q 0.458 0 0 RG q /FormType 1 >> /ProcSet[/PDF/Text] /Resources<< q Q Q /Meta2 9 0 R /BBox [0 0 15.59 16.44] 0 g /ProcSet[/PDF/Text] 0 g 1 i 0 g >> 0 G /BBox [0 0 88.214 35.886] ET /Meta29 42 0 R << 0.564 G /BBox [0 0 88.214 16.44] 1.007 0 0 1.007 411.035 383.934 cm << /F3 17 0 R 200 0 obj /Type /XObject /FormType 1 /Resources<< 0.564 G /Font << >> /FormType 1 Q /Length 69 1 i /Meta95 Do q 0 g BT >> View the full answer. stream q >> /Font << 1 i endstream /FormType 1 endobj stream endobj Thrice of a number = 3x. 0 g /ProcSet[/PDF] /ProcSet[/PDF/Text] BT 1 i Q /Font << 1.014 0 0 1.006 111.416 690.329 cm q /BBox [0 0 88.214 16.44] /Length 59 /Length 77 >> /Matrix [1 0 0 1 0 0] q /Length 70 >> q q 0 g Q 1 g q /Resources<< /Length 59 /Length 70 Q (x) Tj q endstream Q << -0.126 Tw endstream /F3 12.131 Tf >> q Q /Meta368 382 0 R a and b or something else.***. /Font << >> << 672.261 726.464 m /Meta283 297 0 R 1.007 0 0 1.007 45.168 713.666 cm >> << /F3 12.131 Tf Q /Resources<< q 0 w ET q 0 g 1 g /Meta377 Do BT /Meta345 359 0 R /Matrix [1 0 0 1 0 0] 0 g Twice a number decreased by 8 gives 58. 0 g 0 w 0 G << q q q 1.007 0 0 1.007 130.989 383.934 cm 23.216 5.203 TD endobj Q /Length 16

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